Question

what is the axis of symmetry for the following quadratic function: f(x)=1/2(x - 4)^2+3
x = 1/2
x = 4
x=-4
x = 3

Explanation:

Step1: Recall vertex - form of quadratic function

The vertex - form of a quadratic function is $y = a(x - h)^2+k$, and the axis of symmetry is $x = h$.

Step2: Identify values of h

For the function $f(x)=\frac{1}{2}(x - 4)^2+3$, comparing with $y=a(x - h)^2 + k$, we have $h = 4$.

Answer:

$x = 4$