Question

what is the center of the circle (x + 1)^2 + (y - \frac{13}{2})^2 = 101? simplify any fractions.

Explanation:

Step1: Recall circle - standard form

The standard form of a circle is $(x - h)^2+(y - k)^2=r^2$, where $(h,k)$ is the center of the circle.

Step2: Rewrite the given equation

The given equation is $(x + 1)^2+(y-\frac{13}{2})^2 = 101$, which can be written as $(x-(-1))^2+(y - \frac{13}{2})^2=101$.

Answer:

$(-1,\frac{13}{2})$