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what is the central atom hybridization in the following ion? \begin{bma…

Question

what is the central atom hybridization in the following ion?
\begin{bmatrix} ddot{o} \\ vert \\ ddot{o}-s - ddot{o} \\ vert \\ ddot{o} end{bmatrix}^{2 -}
o sp^{3}
o sp^{2}
o sp
o sp^{3}d
o sp^{3}d^{2}

Explanation:

Step1: Determine the number of electron - groups around the central atom

The central atom is sulfur (S). It has 4 bonding pairs (with oxygen atoms) and 0 lone pairs, so the total number of electron - groups is 4.

Step2: Use the electron - group formula for hybridization

The formula for determining hybridization based on the number of electron - groups (n) is: if n = 2, hybridization is sp; if n = 3, hybridization is sp²; if n = 4, hybridization is sp³; if n = 5, hybridization is sp³d; if n = 6, hybridization is sp³d². Here, n = 4, so the hybridization of the central sulfur atom is sp³.

Answer:

sp³