Question

what is the density of an aqueous solution that has a mass of 10.081 g and a volume of 12.5 ml? only include the number without the units for the answer and round your answer to the correct number of significant digits.

Explanation:

Step1: Recall density formula

Density ($
ho$) is given by the formula $
ho = \frac{m}{V}$, where $m$ is mass and $V$ is volume.

Step2: Substitute values

Here, $m = 10.081\ \text{g}$ and $V = 12.5\ \text{mL}$. Substitute into the formula: $
ho=\frac{10.081}{12.5}$.

Step3: Calculate the value

$\frac{10.081}{12.5}=0.80648$. Now, consider significant digits. The mass has 5 significant digits, volume has 3. The result should have 3 significant digits. Rounding $0.80648$ to 3 significant digits gives $0.806$.

Answer:

0.806