Question

what is the equation of the line that is perpendicular to the line y = 6 and passes through the point (-4, -3)?
o x = -4
o x = -3
o x = -\frac{1}{6}
o x = 6

Explanation:

Step1: Analyze the slope of $y = 6$

The line $y=6$ is a horizontal line with slope $m_1 = 0$. A line perpendicular to a horizontal line is a vertical line. The slope of a vertical line is undefined.

Step2: Use the point - form for a vertical line

The equation of a vertical line passing through the point $(x_0,y_0)$ is of the form $x=x_0$. The given point is $(-4,-3)$, where $x_0=-4$. So the equation of the line is $x = - 4$.

Answer:

A. $x=-4$