Question

1. what is the equation of the trendline? do not round, use exactly what excel calculates.

y=1.1432x+30.281

1. how many chirps in 15 seconds would occur when the temperature is 75 degrees f? show all work and round your answer to the nearest tenth.

y=1.1432(75)+30.281 y=116.03 seconds

1. if the crickets chirp 32 times in 15 seconds, what is the estimated temperature outside? show all work and round to the nearest tenth.

Explanation:

Step1: Identify the trend - line equation

The trend - line equation is given as $y = 1.1432x+30.281$, where $y$ is the temperature and $x$ is the number of chirps.

Step2: Solve for the number of chirps when $y = 75$

We substitute $y = 75$ into the equation $y = 1.1432x+30.281$ and solve for $x$.
$75=1.1432x + 30.281$
Subtract 30.281 from both sides:
$75−30.281=1.1432x$
$44.719 = 1.1432x$
Then divide both sides by 1.1432:
$x=\frac{44.719}{1.1432}\approx39.1$

Step3: Solve for the temperature when $x = 32$

Substitute $x = 32$ into the equation $y = 1.1432x+30.281$.
$y=1.1432\times32 + 30.281$
$y = 36.5824+30.281$
$y=66.8634\approx66.9$

Answer:

1. The equation of the trend - line is $y = 1.1432x+30.281$.
2. The number of chirps is approximately $39.1$.
3. The estimated temperature is approximately $66.9$ degrees F.