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what is the force acting on an object that experienced a 925 n·s impuls…

Question

what is the force acting on an object that experienced a 925 n·s impulse over 6 s? (a) 5550 n (b) $\frac{925}{6}$ n (c) $\frac{6}{925}$ n (d) 0 n

Explanation:

Step1: Recall impulse - force formula

The formula for impulse \(J\) is \(J = F\Delta t\), where \(J\) is impulse, \(F\) is force and \(\Delta t\) is the time interval. We need to solve for \(F\), so \(F=\frac{J}{\Delta t}\).

Step2: Substitute given values

Given \(J = 925\ N\cdot s\) and \(\Delta t=6\ s\), substituting into the formula \(F=\frac{925}{6}\ N\).

Answer:

B. \(\frac{925}{6}\ N\)