Question

what is the measure of side nd in rhombus ands? question 3

Explanation:

Step1: Recall rhombus property

The diagonals of a rhombus are perpendicular bisectors of each other. Let the half - lengths of the diagonals be \(a = 7\) and \(b=24\).

Step2: Apply Pythagorean theorem

In the right - triangle formed by the half - diagonals and a side of the rhombus, if the side length is \(s\), then \(s=\sqrt{a^{2}+b^{2}}\) according to the Pythagorean theorem \(c = \sqrt{a^{2}+b^{2}}\) (where \(c\) is the hypotenuse of a right - triangle and \(a\), \(b\) are the legs).

Step3: Calculate side length

Substitute \(a = 7\) and \(b = 24\) into the formula: \(s=\sqrt{7^{2}+24^{2}}=\sqrt{49 + 576}=\sqrt{625}=25\). So the length of side \(ND\) is 25.

Answer:

A. 25