Question

what is the product?
$(7x^{2}y^{3})(3x^{5}y^{8})$
$\bigcirc$ $10x^{7}y^{11}$
$\bigcirc$ $10x^{10}y^{24}$
$\bigcirc$ $21x^{7}y^{11}$
$\bigcirc$ $21x^{10}y^{24}$

Explanation:

Step1: Multiply the coefficients

$7 \times 3 = 21$

Step2: Multiply $x$-terms (add exponents)

$x^2 \times x^5 = x^{2+5} = x^7$

Step3: Multiply $y$-terms (add exponents)

$y^3 \times y^8 = y^{3+8} = y^{11}$

Step4: Combine all products

$21 \times x^7 \times y^{11}$

Answer:

21$x^7y^{11}$ (Option: 21$x^7y^{11}$)