Question

what product is formed when ch₃ch₂ch₂ch₂ - sh is oxidized?
ch₃ch₂ch₂ch
ch₃ch₂ch₂ch₂ - s - s - ch₂ch₂ch₂ch₃
ch₃ch₂ch₂ - c - s - oh
ch₃ch₂ch₂ch₂ - s - ch₂ch₂ch₂ch₃
ch₃ch₂ch₂ch₂ - s

Explanation:

Step1: Recall oxidation of thiols

Thiols ($R - SH$) are oxidized to disulfides ($R - S - S - R$) in the presence of oxidizing agents.

Step2: Identify the product

For $CH_3CH_2CH_2CH_2 - SH$, when oxidized, the product is $CH_3CH_2CH_2CH_2 - S - S - CH_2CH_2CH_2CH_3$.

Answer:

$CH_3CH_2CH_2CH_2 - S - S - CH_2CH_2CH_2CH_3$