Question

1. what is the resulting volume of an 6403 ml balloon at celsius boiling point of water that was placed in a container of ice water at 8°c?

Explanation:

Step1: Identificar las magnitudes iniciales y finales

Temperatura inicial $T_1 = 100^{\circ}C=(100 + 273)K=373K$, volumen inicial $V_1 = 6403mL$, temperatura final $T_2=(8 + 273)K = 281K$.

Step2: Aplicar la ley de Charles

La ley de Charles establece que $\frac{V_1}{T_1}=\frac{V_2}{T_2}$. Re - arreglamos la ecuación para despejar $V_2$: $V_2=\frac{V_1\times T_2}{T_1}$.

Step3: Sustituir valores

$V_2=\frac{6403mL\times281K}{373K}$.
$V_2=\frac{1799243}{373}mL\approx4824mL$.

Answer:

$4824mL$