Question

what is shown on the hanger diagram. now keep going. recoroth sides by in order to have k remaining on the left.\\(\

$$\begin{array}{rccr}3k + 29&=&74\\\\-29&&-29\\\\\\hline 3k&=&45\\\\\\cline{1 - 1}\\cline{3 - 3}\\square&&\\square\\end{array}$$

\\)

Explanation:

Step1: Identify the operation needed

To isolate \( k \) from \( 3k = 45 \), we need to divide both sides by the coefficient of \( k \), which is 3.

Step2: Perform the division on both sides

Divide \( 3k \) by 3: \( \frac{3k}{3}=k \)
Divide 45 by 3: \( \frac{45}{3} = 15 \)

Answer:

The number to divide both sides by is 3, and the result on the right side is 15. So the boxes should be filled with 3 (left) and 15 (right).