Question

what slope - intercept form equation represents the line? 4. 5. 6.

Explanation:

Step1: Recall slope - intercept form

The slope - intercept form of a line is $y = mx + b$, where $m$ is the slope and $b$ is the y - intercept.

Step2: For graph 4

Find two points, say $(0, - 2)$ and $(1,0)$. The slope $m=\frac{y_2 - y_1}{x_2 - x_1}=\frac{0-( - 2)}{1 - 0}=2$, and the y - intercept $b=-2$. So the equation is $y = 2x-2$.

Step3: For graph 5

The line is horizontal. The slope $m = 0$, and it passes through $(0,-4)$. So the equation is $y=-4$ (since $y=0x - 4$).

Step4: For graph 6

Find two points, say $(0,4)$ and $(4,0)$. The slope $m=\frac{0 - 4}{4 - 0}=-1$, and the y - intercept $b = 4$. So the equation is $y=-x + 4$.

Answer:

For graph 4: $y = 2x-2$
For graph 5: $y=-4$
For graph 6: $y=-x + 4$