Question

what is the solution to the system of equations?
$\begin{cases} x - 2y = 8 \\ -2x + y = 2 end{cases}$
(make sure you put parenthesis around your two numbers in the format of (x, y))

Explanation:

Step1: Isolate $y$ from 2nd equation

$y = 2x + 2$

Step2: Substitute $y$ into 1st equation

$x - 2(2x + 2) = 8$

Step3: Simplify to solve for $x$

$x - 4x - 4 = 8 \\
-3x = 12 \\
x = -4$

Step4: Substitute $x=-4$ into $y=2x+2$

$y = 2(-4) + 2 = -8 + 2 = -6$

Answer:

$(-4, -6)$