QUESTION IMAGE
Question
what is the solution to this system of linear equations?
3x - 2y = 14
5x + y = 32
(3, 5)
(6, 2)
(8, -1)
(14, -18)
Step1: Solve the second equation for y
From \(5x + y = 32\), we can express \(y\) as \(y = 32 - 5x\).
Step2: Substitute y into the first equation
Substitute \(y = 32 - 5x\) into \(3x - 2y = 14\):
\[
$$\begin{align*}
3x - 2(32 - 5x)&= 14\\
3x - 64 + 10x&= 14\\
13x - 64&= 14\\
13x&= 14 + 64\\
13x&= 78\\
x&= \frac{78}{13}\\
x&= 6
\end{align*}$$
\]
Step3: Find y using x = 6
Substitute \(x = 6\) into \(y = 32 - 5x\):
\(y = 32 - 5\times6 = 32 - 30 = 2\)
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(6, 2)