QUESTION IMAGE
Question
what is m∠1? m∠1 = (square^{circ})
Step1: Recall angle - sum property of a triangle
The sum of the interior angles of a triangle is 180°. Let the third - interior angle of the triangle be \(x\). So \(x + 69^{\circ}+72^{\circ}=180^{\circ}\).
Step2: Calculate the third - interior angle
\[
$$\begin{align*}
x&=180^{\circ}-(69^{\circ} + 72^{\circ})\\
x&=180^{\circ}-141^{\circ}\\
x& = 39^{\circ}
\end{align*}$$
\]
Step3: Use the linear - pair property
\(\angle1\) and the third - interior angle \(x\) form a linear pair. A linear pair of angles is supplementary, i.e., their sum is 180°. So \(m\angle1+x = 180^{\circ}\).
Step4: Calculate \(m\angle1\)
\[
$$\begin{align*}
m\angle1&=180^{\circ}-x\\
m\angle1&=180^{\circ}-39^{\circ}\\
m\angle1&=141^{\circ}
\end{align*}$$
\]
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