Question

what is the starting value in the equation $f(x) = 11(1.7)^{x - 1}$? (1 point) the starting value is \square. check answer remaining attempts : 3

Explanation:

Step1: Recall the form of exponential function

The general form of an exponential function is \( f(x) = a(b)^{x - h}+k \), but for the starting value (initial value), we consider when \( x = 1 \) (since the exponent is \( x - 1 \)). When \( x = 1 \), the exponent \( x - 1=0 \), and any non - zero number to the power of 0 is 1.

Step2: Substitute \( x = 1 \) into the function

Given the function \( f(x)=11(1.7)^{x - 1} \), when \( x = 1 \), we have \( f(1)=11\times(1.7)^{1 - 1} \). Since \( (1.7)^{0}=1 \), then \( f(1)=11\times1 = 11 \).

Answer:

11