Question

what is the value of x in the triangle?
triangle with legs 10, 10 and hypotenuse x
a. $10\sqrt{2}$
b. 10
c. 20
d. $20\sqrt{2}$
e. $10\sqrt{3}$

Explanation:

Step1: Identify triangle type

It's an isosceles right triangle (legs=10, right angle).

Step2: Apply Pythagorean theorem

Hypotenuse \(x = \sqrt{10^2 + 10^2}\)

Step3: Calculate x

\(x = \sqrt{200} = 10\sqrt{2}\)

Answer:

A. \(10\sqrt{2}\)