Question

what volume in liters of a 0.724 m nai solution contains 0.405 mol of nai ?

Explanation:

Step1: Recall molarity formula

Molarity \( M = \frac{\text{mol solute}}{\text{volume solution (L)}} \), rearrange to solve for volume: \( \text{Volume (L)} = \frac{\text{mol solute}}{M} \)

Step2: Substitute given values

Given \( \text{mol NaI} = 0.405 \), \( M = 0.724 \)
\( \text{Volume} = \frac{0.405}{0.724} \)

Step3: Calculate the result

Perform division: \( \frac{0.405}{0.724} \approx 0.559 \)

Answer:

0.559 liters

(Factor setup for the diagram:
Starting amount: \( 0.405 \) mol NaI
Multiplication factor: \( \frac{1\ \text{L}}{0.724\ \text{mol NaI}} \))