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whats wrong with this coder? function start() { move(); go(); go(); } f…

Question

whats wrong with this coder? function start() { move(); go(); go(); } function go() { move(); move(); } function go() { move(); move(); } the go function is called twice the go function has a syntax error the go function has been defined twice go is not a command that karel understands

Explanation:

Brief Explanations

In JavaScript, a function with the same name cannot be defined multiple times. Here, the go function is defined twice which will cause an error as the second definition will overwrite the first one in non - strict mode and in strict mode it will throw a syntax error.

Answer:

The go function has been defined twice