Question

a wheel barrow is used to lift a 200 lb load. the length from the center of the wheel to the center of the load is 2 ft. the length from the wheel to the effort is 5 ft.

1. illustrate and annotate the lever system described above.
2. what is the ideal mechanical advantage of the system?

formula substitute / solve final answer

1. using static equilibrium calculations, calculate the ideal effort force needed to overcome the resistance force in the system.

formula substitute / solve final answer
a medical technician uses a pair of four - inch long tweezers to remove a wood sliver from a patient. the technician is applying 1 lb of squeezing force to the tweezers. if more than 1/5 lb of force is applied to the sliver, it will break and become difficult to remove.

1. sketch and annotate the lever system described above.

Explanation:

Step1: Recall ideal - mechanical - advantage formula

The formula for the ideal mechanical advantage (IMA) of a lever is $IMA=\frac{D_{e}}{D_{r}}$, where $D_{e}$ is the effort - distance and $D_{r}$ is the resistance - distance.

Step2: Identify values

Given that $D_{e}=5\ ft$ (distance from the wheel to the effort) and $D_{r}=2\ ft$ (distance from the center of the wheel to the center of the load).

Step3: Calculate IMA

$IMA=\frac{D_{e}}{D_{r}}=\frac{5}{2}=2.5$

Step4: Recall static - equilibrium formula for levers

The static - equilibrium formula for levers is $F_{e}\times D_{e}=F_{r}\times D_{r}$, where $F_{e}$ is the effort force, $D_{e}$ is the effort distance, $F_{r}$ is the resistance force, and $D_{r}$ is the resistance distance.

Step5: Identify values for force calculation

We know that $F_{r} = 200\ lb$, $D_{e}=5\ ft$, and $D_{r}=2\ ft$.

Step6: Solve for effort force

From $F_{e}\times D_{e}=F_{r}\times D_{r}$, we can express $F_{e}=\frac{F_{r}\times D_{r}}{D_{e}}$. Substituting the values: $F_{e}=\frac{200\times2}{5}=80\ lb$

Answer:

1. The ideal mechanical advantage of the system is 2.5.
2. The ideal effort force needed to overcome the resistance force in the system is 80 lb.