Question

when the following molecular equation is balanced using the smallest possible integer coefficients, the values of these coefficients are: hcl (aq) + ba(oh)2 (aq) → bacl2 (aq) + h2o (l). an error has been detected in your answer. check for typos, miscalculations etc. before submitting your answer. try another version 3 item attempts remaining. use the references to access important values if needed for this question.

Explanation:

Step1: Write the un - balanced equation

$HCl(aq)+Ba(OH)_2(aq)
ightarrow BaCl_2(aq) + H_2O(l)$

Step2: Balance the chlorine atoms

There are 2 chlorine atoms in $BaCl_2$ and 1 in $HCl$. So, we put a 2 in front of $HCl$. The equation becomes $2HCl(aq)+Ba(OH)_2(aq)
ightarrow BaCl_2(aq)+H_2O(l)$

Step3: Balance the hydrogen and oxygen atoms

On the left - hand side, we have 4 hydrogen atoms ($2$ from $2HCl$ and $2$ from $Ba(OH)_2$) and 2 oxygen atoms from $Ba(OH)_2$. On the right - hand side, we have 2 hydrogen atoms and 1 oxygen atom in $H_2O$. To balance hydrogen and oxygen, we put a 2 in front of $H_2O$. The balanced equation is $2HCl(aq)+Ba(OH)_2(aq)
ightarrow BaCl_2(aq)+2H_2O(l)$

Answer:

$2$; $1$; $1$; $2$