Question

when methane is burned with oxygen, the products are carbon dioxide and water. if you produce 18 grams of water from 8 grams of methane and 32 grams of oxygen, how many grams of carbon dioxide were produced in the reaction?

a. 40

b. 22

c. 34

d. 58

e. 18

Explanation:

Step1: Apply the Law of Conservation of Mass

The total mass of reactants equals the total mass of products. The reactants are methane (8 g) and oxygen (32 g), so the total mass of reactants is $8 + 32 = 40$ g.

Step2: Calculate the mass of carbon dioxide

Let the mass of carbon dioxide be $x$. The mass of water is 18 g. So, $8 + 32 = x + 18$. Solving for $x$, we get $x = 40 - 18 = 22$ g.

Answer:

b. 22