Question

when point f is reflected in $y = x$, the image is located at $f(6, -9)$. point f is located at (-9, 6)

Explanation:

Step1: Recall reflection over $y=x$ rule

A reflection of a point $(x,y)$ over the line $y=x$ swaps the $x$ and $y$-coordinates, resulting in $(y,x)$.

Step2: Reverse the reflection rule

If the reflected point is $F'(6, -9)$, we swap its coordinates again to find the original point $F$.

Answer:

$(-9, 6)$