Question

when using a calorimeter, the initial temperature of a metal is 70.4°c. the initial temperature of the water is 23.6°c. at the end of the experiment, the final equilibrium temperature of the water is 29.8°c. what is the final temperature of the metal? °c what is the temperature change of the water? °c what is the temperature change of the metal? °c

Explanation:

Step1: Determine final metal temperature

In a calorimetry experiment, the final temperature of the metal and water are the same at equilibrium. So the final temperature of the metal is the final equilibrium temperature of the water.
$T_{metal - final}=29.8^{\circ}C$

Step2: Calculate water temperature - change

The formula for temperature - change is $\Delta T=T_{final}-T_{initial}$. For water, $T_{initial}=23.6^{\circ}C$ and $T_{final}=29.8^{\circ}C$.
$\Delta T_{water}=29.8 - 23.6=6.2^{\circ}C$

Step3: Calculate metal temperature - change

For the metal, $T_{initial}=70.4^{\circ}C$ and $T_{final}=29.8^{\circ}C$. Using the formula $\Delta T=T_{final}-T_{initial}$.
$\Delta T_{metal}=29.8 - 70.4=- 40.6^{\circ}C$

Answer:

Final temperature of the metal: $29.8^{\circ}C$
Temperature change of the water: $6.2^{\circ}C$
Temperature change of the metal: $-40.6^{\circ}C$