Question

when using a series circuit to connect four small light bulbs, which statement is most accurate? a if one bulb fails, the other three can remain operational. b the current passing through each bulb is the same. c by removing light bulbs in the series, it will draw less current from the power source. d as more light bulbs are added in series, the brightness of the bulbs will stay the same.

Explanation:

• Option A: In a series circuit, all components are in a single path. If one bulb fails (opens the circuit), the entire circuit is broken, so no bulbs work. This is incorrect.
• Option B: In a series circuit, the current is the same through every component, as there is only one path for the current to flow. This is correct.
• Option C: Removing bulbs from a series circuit decreases total resistance. By Ohm's Law ($I=\frac{V}{R}$), with constant voltage, lower resistance leads to higher current drawn from the source. This is incorrect.
• Option D: Adding more bulbs in series increases total resistance, lowering the circuit current. Since bulb brightness depends on power ($P=I^2R$), lower current reduces brightness. This is incorrect.

Answer:

B. The current passing through each bulb is the same.