Question

where does the trend line touch or cross the y - axis? is the slope positive or negative? positive \\(y = \square x + \square\\)

Explanation:

Step1: Identify Y-intercept

The trend line crosses the y-axis at $x=0$, $y=10$.

Step2: Determine slope sign

As $x$ increases, $y$ decreases, so slope is negative.

Step3: Calculate slope value

Use two points on the line: $(2,0)$ and $(5,4)$.
Slope $m = \frac{4-0}{5-2} = \frac{4}{-3} = -\frac{4}{3}$

Step4: Write line equation

Use $y=mx+b$, where $b=10$, $m=-\frac{4}{3}$.

Answer:

Where does the trend line touch or cross the Y-axis? $\boldsymbol{10}$
Is the slope positive or negative? $\boldsymbol{negative}$
$y = \boldsymbol{-\frac{4}{3}}x + \boldsymbol{10}$