Question

1. which is equivalent to $(3x - 4)^4$.$\bigcirc$ $x^4 + 4x^3y + 6x^2y^2 + 4xy^3 + y^4LXB0\bigcirc$ $(3x + 4)(3x + 4)(3x - 4)(3x - 4)$$\bigcirc$ $9x^2 - 24x + 16$

Explanation:

Step1: Recall exponent definition

For any expression $a^n$, it means multiplying $a$ by itself $n$ times.

Step2: Apply to the given expression

Here, $a=(3x-4)$ and $n=4$, so $(3x-4)^4$ is $(3x-4)$ multiplied 4 times.

Step3: Eliminate incorrect options

• Option1: Is the binomial expansion of $(x+y)^4$, irrelevant.
• Option3: Equals $(3x+4)^2(3x-4)^2 = [(3x+4)(3x-4)]^2=(9x^2-16)^2$, not equal to $(3x-4)^4$.
• Option4: Is the expansion of $(3x-4)^2$, not the 4th power.

Answer:

B. $(3x - 4)(3x - 4)(3x - 4)(3x - 4)$