Question

which expression is equivalent to $x^{-3} \cdot x^{-3} \cdot x^{2}$?
$\bigcirc$ $x^{-12}$
$\bigcirc$ $\frac{1}{x^{4}}$
$\bigcirc$ $\frac{1}{x^{-4}}$
$\bigcirc$ $x^{18}$

Explanation:

Step1: Add exponents of like bases

$x^{-3 + (-3) + 2} = x^{-4}$

Step2: Rewrite negative exponent

$x^{-4} = \frac{1}{x^4}$

Answer:

$\boldsymbol{\frac{1}{x^4}}$ (Option B)