Question

which of the following is a counterexample for this conditional statement? if a rectangle has a perimeter of 20, then its area is 24. a rectangle with sides measuring 3 and 7 a rectangle with sides measuring 4 and 5 a rectangle with sides measuring 5 and 6 a rectangle with sides measuring 10 and 2

Explanation:

Step1: Calculate perimeter

For a rectangle with length $l$ and width $w$, perimeter $P = 2(l + w)$. For a rectangle with sides 4 and 5, $P=2(4 + 5)=18
eq20$, so it's not valid. For sides 5 and 6, $P = 2(5+6)=22
eq20$. For sides 10 and 2, $P=2(10 + 2)=24
eq20$. For sides 3 and 7, $P=2(3 + 7)=20$.

Step2: Calculate area

Area $A=l\times w$. For sides 3 and 7, $A = 3\times7 = 21
eq24$.

Answer:

a rectangle with sides measuring 3 and 7