Question

which of the following molecules demonstrates a square pyramidal molecular structure? xeo3 ch4 xef4 ccl4

Explanation:

Use VSEPR (Valence - Shell Electron - Pair Repulsion) theory. For $XeO_3$, Xe has 8 valence electrons, forms 3 bonds with O and has 1 lone - pair, resulting in a trigonal pyramidal shape. For $CH_4$, C has 4 valence electrons, forms 4 bonds with H and has no lone - pairs, giving a tetrahedral shape. For $CCl_4$, C has 4 valence electrons, forms 4 bonds with Cl and has no lone - pairs, also tetrahedral. For $XeF_4$, Xe has 8 valence electrons, forms 4 bonds with F and has 2 lone - pairs. According to VSEPR, the electron - pair geometry is octahedral and the molecular geometry is square planar.

Answer:

C. $XeF_4$