Question

which of the following values are solutions to the inequality $3 - 2x < -10$?
i. $-2$ ii. $2$ iii. $10$
answer
none
i only
ii only
iii only
i and ii
i and iii
ii and iii
i, ii and iii
submit answer

Explanation:

Step1: Isolate the x term

Subtract 3 from both sides:
$3 - 2x - 3 < -10 - 3$
$-2x < -13$

Step2: Solve for x (reverse inequality)

Divide by -2, reverse inequality sign:
$\frac{-2x}{-2} > \frac{-13}{-2}$
$x > 6.5$

Step3: Test given values

• For $x=-2$: $-2 > 6.5$ is false
• For $x=2$: $2 > 6.5$ is false
• For $x=10$: $10 > 6.5$ is true

Answer:

III only