Question

which are the prime factors of the polynomial (24x^4 - 3x)? choose three correct answers.
options: (3x), ((4x^2 + 1)), ((x - 1)), ((2x^2 - 2x + 1)), ((2x - 1)), (2x), ((4x^2 + 2x + 1))

Explanation:

Step1: Factor out GCF

$24x^4 - 3x = 3x(8x^3 - 1)$

Step2: Apply difference of cubes

$8x^3 - 1 = (2x)^3 - 1^3 = (2x-1)(4x^2+2x+1)$

Step3: Combine all prime factors

$24x^4 - 3x = 3x(2x-1)(4x^2+2x+1)$

Answer:

$3x$, $(2x-1)$, $(4x^2+2x+1)$