Question

which are the roots of the quadratic function $f(b) = b^2 - 75$? select two options. $\square$ $b = 5\sqrt{3}$ $\square$ $b = -5\sqrt{3}$ $\square$ $b = 3\sqrt{5}$ $\square$ $b = -3\sqrt{5}$ $\square$ $b = 25\sqrt{3}$

Explanation:

Step1: Set function to zero

\(b^2 - 75 = 0\)

Step2: Isolate \(b^2\)

\(b^2 = 75\)

Step3: Take square roots

\(b = \pm\sqrt{75} = \pm5\sqrt{3}\)

Answer:

A. \(b = 5\sqrt{3}\), B. \(b = -5\sqrt{3}\)