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which shows the image of quadrilateral abcd after the transformation r₀…

Question

which shows the image of quadrilateral abcd after the transformation r₀, 90°?

Explanation:

Step1: Recall rotation rule

The transformation $R_{0,90^{\circ}}$ is a 90 - degree counter - clockwise rotation about the origin. The rule for a 90 - degree counter - clockwise rotation about the origin for a point $(x,y)$ is $(x,y)\to(-y,x)$.

Step2: Apply rule to vertices

Let's assume the coordinates of the vertices of quadrilateral $ABCD$ are $A(x_1,y_1)$, $B(x_2,y_2)$, $C(x_3,y_3)$ and $D(x_4,y_4)$. After rotation, the new coordinates will be $A'(-y_1,x_1)$, $B'(-y_2,x_2)$, $C'(-y_3,x_3)$ and $D'(-y_4,x_4)$. Plot these new points to get the image of the quadrilateral.

Since no options are provided, we can't give a specific final - answer in terms of a choice. But the general way to find the image is as described above.

Answer:

Step1: Recall rotation rule

The transformation $R_{0,90^{\circ}}$ is a 90 - degree counter - clockwise rotation about the origin. The rule for a 90 - degree counter - clockwise rotation about the origin for a point $(x,y)$ is $(x,y)\to(-y,x)$.

Step2: Apply rule to vertices

Let's assume the coordinates of the vertices of quadrilateral $ABCD$ are $A(x_1,y_1)$, $B(x_2,y_2)$, $C(x_3,y_3)$ and $D(x_4,y_4)$. After rotation, the new coordinates will be $A'(-y_1,x_1)$, $B'(-y_2,x_2)$, $C'(-y_3,x_3)$ and $D'(-y_4,x_4)$. Plot these new points to get the image of the quadrilateral.

Since no options are provided, we can't give a specific final - answer in terms of a choice. But the general way to find the image is as described above.