Question

which two expressions are equivalent?
select two correct answers.
$(5 \cdot \frac{1}{2}p) - (2 \cdot 7)$
$\left(\frac{1}{2}p \cdot 5\
ight) - (7 \cdot 2)$
$\left(\frac{1}{2}p \cdot 5 \cdot 7\
ight) - 2$
$\left(\frac{1}{2}p \cdot 5 - 2\
ight) \cdot 7$
$5\left(\frac{1}{2}p - 2\
ight) \cdot 7$

step 1: what kind of problem is it? (circle)
pemdas | distributive | 1-step eq | 2-step eq |
area | perimeter | volume | inequality |
ratio/rate | percent | substitue & check |
other: ____

step 2:what do i use? (rule/formula/steps)
____

step 3: what am i finding?
circle the question in the problem.

step 4: solve + check
show work below.

the length of ms. palmers camping trailer is x feet. the

Explanation:

Step1: Analyze first expression

Simplify $(5 \cdot \frac{1}{2}p) - (2 \cdot 7)$:
$5 \cdot \frac{1}{2}p = \frac{5}{2}p$, $2 \cdot 7 = 14$, so it becomes $\frac{5}{2}p - 14$.

Step2: Analyze second expression

Simplify $(\frac{1}{2}p \cdot 5 \cdot 7) - 2$:
$\frac{1}{2}p \cdot 5 \cdot 7 = \frac{35}{2}p$, so it becomes $\frac{35}{2}p - 2$.

Step3: Analyze third expression

Simplify $5(\frac{1}{2}p - 2) \cdot 7$:
Use distributive property: $5 \cdot 7 \cdot \frac{1}{2}p - 5 \cdot 7 \cdot 2 = \frac{35}{2}p - 70$.

Step4: Analyze fourth expression

Simplify $(\frac{1}{2}p \cdot 5) - (7 \cdot 2)$:
$\frac{1}{2}p \cdot 5 = \frac{5}{2}p$, $7 \cdot 2 = 14$, so it becomes $\frac{5}{2}p - 14$.

Step5: Analyze fifth expression

Simplify $(\frac{1}{2}p \cdot 5 - 2) \cdot 7$:
Use distributive property: $\frac{1}{2}p \cdot 5 \cdot 7 - 2 \cdot 7 = \frac{35}{2}p - 14$.

Answer:

1. $(5 \cdot \frac{1}{2}p) - (2 \cdot 7)$
2. $(\frac{1}{2}p \cdot 5) - (7 \cdot 2)$