Question

which type of reaction occurs in the core of a nuclear reactor in a nuclear power plant?
○ hcl+naoh→h₂o+nacl
○ ( ce{_{92}^{235}u + _{0}^{1}n -> _{38}^{90}sr + _{54}^{140}xe + 3_{0}^{1}n} )
○ ( ce{_{38}^{90}sr + _{54}^{140}xe + 3_{0}^{1}n -> _{92}^{235}u + _{0}^{1}n} )
○ ( ce{c_{10}h_8 + 12o_2 -> 10co_2 + 4h_2o} )

Explanation:

1. Analyze the first option: $\ce{HCl + NaOH -> H_{2}O + NaCl}$ is an acid - base neutralization reaction, not a nuclear reaction.
2. Analyze the second option: $\ce{_{92}^{235}U + _{0}^{1}n -> _{38}^{90}Sr + _{54}^{140}Xe + 3_{0}^{1}n}$ shows the fission of uranium - 235 when bombarded with a neutron, producing smaller nuclei (strontium - 90, xenon - 140) and more neutrons. Nuclear power plants use nuclear fission reactions in their reactors.
3. Analyze the third option: $\ce{_{38}^{90}Sr + _{54}^{140}Xe + 3_{0}^{1}n -> _{92}^{235}U + _{0}^{1}n}$ is the reverse of a fission reaction, representing a nuclear fusion - like or a non - typical reaction for a nuclear power plant (nuclear power plants use fission, not this reverse process).
4. Analyze the fourth option: $\ce{C_{10}H_{8}+12O_{2} -> 10CO_{2}+4H_{2}O}$ is a combustion reaction (burning of a hydrocarbon), not a nuclear reaction.

Answer:

$\boldsymbol{\ce{_{92}^{235}U + _{0}^{1}n -> _{38}^{90}Sr + _{54}^{140}Xe + 3_{0}^{1}n}}$ (the second option)