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which value must be added to the expression ( x^2 + 16x ) to make it a …

Question

which value must be added to the expression ( x^2 + 16x ) to make it a perfect - square trinomial?
( \bigcirc 8 )
( \bigcirc 32 )
( \bigcirc 64 )
( \bigcirc 256 )

Explanation:

Step1: Identify linear term coefficient

The linear term is $16x$, so its coefficient is $16$.

Step2: Halve the coefficient

$\frac{16}{2} = 8$

Step3: Square the result

$8^2 = 64$

Answer:

64 (Option C)