Question

write a balanced chemical equation for the decomposition of solid sodium sulfide in aqueous solution. a na₂s(s)→na⁺(aq)+s(s) b nas₂(s)→na⁺(aq)+2s²⁻(aq) c na₂s(aq)→2na⁺(s)+s²⁻(s) d na₂s(s)→2na⁺(aq)+s²⁻(aq)

Explanation:

Step1: Analyze sodium sulfide formula

Sodium sulfide has the formula $Na_2S$. When it dissociates in aqueous solution, it breaks into its constituent ions.

Step2: Determine ion - charges and balance

Sodium has a +1 charge ($Na^+$) and sulfide has a - 2 charge ($S^{2 - }$). For every $Na_2S$ unit, there are 2 sodium ions and 1 sulfide ion. The correct dissociation equation is $Na_2S(s)
ightarrow2Na^+(aq)+S^{2 - }(aq)$.

Answer:

D. $Na_2S(s)
ightarrow2Na^+(aq)+S^{2 - }(aq)$