Question

write the equation in slope-intercept form. $4x - 3y + 7 = 7x + 2y - 11$
a) $y = -\frac{3}{5}x + \frac{18}{5}$
b) $y = \frac{3}{5}x - \frac{18}{5}$
c) $y = 3x - 18$
d) $5y = -3x + 18$

Explanation:

Step1: Gather x terms on one side

Subtract $4x$ from both sides:
$$-3y + 7 = 3x + 2y - 11$$

Step2: Gather y terms on one side

Subtract $2y$ from both sides:
$$-5y + 7 = 3x - 11$$

Step3: Isolate the y-term

Subtract 7 from both sides:
$$-5y = 3x - 18$$

Step4: Solve for y (slope-intercept)

Divide all terms by $-5$:
$$y = -\frac{3}{5}x + \frac{18}{5}$$

Answer:

A) $y = -\frac{3}{5}x + \frac{18}{5}$