Question

$\log_{6} \frac{1}{36} = -2$ write in exponential form.$\frac{6}{36} = -2$$36^{-2} = \frac{1}{6}$$6^{-2} = \frac{1}{36}$$36^{6} = -2$

Explanation:

Step1: Recall log-exponential conversion rule

For $\log_b a = c$, exponential form is $b^c = a$

Step2: Match values to the rule

Here, $b=6$, $c=-2$, $a=\frac{1}{36}$

Step3: Substitute into exponential form

$6^{-2} = \frac{1}{36}$

Answer:

$6^{-2} = \frac{1}{36}$ (corresponding to the orange option)