Question

write $b^k = m$ into logarithmic form.
$log_b m = k$
$log_m k = b$
$log_b k = m$
$log_k m = b$

Explanation:

Step1: Recall log-exponential relationship

By definition, if $b^k = m$ (where $b>0, b
eq1$), the logarithmic form is $\log_{b} m = k$.

Step2: Match with given options

Compare the derived form to the provided choices.

Answer:

A. $\log_{b} m = k$