Question

write the standard form of the equation of the circle with its center at (-7,0), and a radius of 3. what is the equation of the circle in standard form?

Explanation:

Step1: Recall the standard - form of a circle equation

The standard - form of the equation of a circle is $(x - h)^2+(y - k)^2=r^2$, where $(h,k)$ is the center of the circle and $r$ is the radius.

Step2: Identify the values of $h$, $k$, and $r$

Given that the center is $(-7,0)$, so $h=-7$, $k = 0$, and the radius $r = 3$.

Step3: Substitute the values into the formula

Substitute $h=-7$, $k = 0$, and $r = 3$ into $(x - h)^2+(y - k)^2=r^2$. We get $(x-(-7))^2+(y - 0)^2=3^2$.

Step4: Simplify the equation

$(x + 7)^2+y^2=9$.

Answer:

$(x + 7)^2+y^2=9$