Question

write the symbol of each neutral element based on its noble gas shorthand configuration: ar4s²3d⁷ he2s²2p² xe6s²

Explanation:

Step1: Determine electrons from [Ar] configuration

Argon (Ar) has 18 electrons. Adding 2 electrons from 4s² and 7 electrons from 3d⁷, we have 18 + 2+ 7 = 27 electrons. The element with 27 electrons is Cobalt (Co).

Step2: Determine electrons from [He] configuration

Helium (He) has 2 electrons. Adding 2 electrons from 2s² and 2 electrons from 2p², we have 2+2 + 2= 6 electrons. The element with 6 electrons is Carbon (C).

Step3: Determine electrons from [Xe] configuration

Xenon (Xe) has 54 electrons. Adding 2 electrons from 6s², we have 54+ 2 = 56 electrons. The element with 56 electrons is Barium (Ba).

Answer:

1. Co
2. C
3. Ba