Question

xy and jk form four right angles
m∠jpx = 90°
xy ⊥ jk
p is the mid - point of xy
xp = yp
jp = kp

Explanation:

Step1: Analyze perpendicular lines

If two lines are perpendicular, they form four right - angles. In the figure, if $\overline{XY}$ and $\overline{JK}$ are perpendicular, then $\overline{XY}$ and $\overline{JK}$ form four right angles, $m\angle JPX = 90^{\circ}$ and $\overline{XY}\perp\overline{JK}$.

Step2: Analyze mid - point properties

Just because two lines intersect at a point $P$ does not necessarily mean that $P$ is the mid - point of either line segment. There is no indication in the figure that $P$ is the mid - point of $\overline{XY}$, so we cannot say $XP = YP$. Also, there is no information to suggest that $JP=KP$.

Answer:

$\overline{XY}$ and $\overline{JK}$ form four right angles, $m\angle JPX = 90^{\circ}$, $\overline{XY}\perp\overline{JK}$