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you will need to make use of an important property of square roots \\(\…

Question

you will need to make use of an important property of square roots
\\(\sqrt{x \cdot y} = \sqrt{x} \cdot \sqrt{y}\\)
this says that you can break up the number under the square root into the perfect square and the leftovers. for example (using the
\\(\sqrt{28} = \sqrt{4} \cdot \sqrt{7} = 2\sqrt{7}\\)
part a
express \\(\sqrt{75}\\) in the form \\(a\sqrt{b}\\)
give the value of \\(a\\) followed by the value of \\(b\\) separated by a comma.
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Explanation:

Step1: Factor out perfect square

$\sqrt{75} = \sqrt{25 \cdot 3}$

Step2: Apply square root product rule

$\sqrt{25 \cdot 3} = \sqrt{25} \cdot \sqrt{3}$

Step3: Simplify perfect square root

$\sqrt{25} \cdot \sqrt{3} = 5\sqrt{3}$

Answer:

5, 3