Question

d. can you prepare 1 liter of a 0.5 - molar glucose solution? show your work here. water’s capacity as a versatile solvent complements the other properties discussed in this chapter. since these remarkable properties allow water to support life on earth so well, scientists who seek life elsewhere in the universe look for water as a sign that a planet might sustain life. e. define molarity.

Explanation:

d.

Step1: Recall molarity formula

Molarity (M) = $\frac{n}{V}$, where $n$ is the number of moles and $V$ is the volume of the solution in liters.

Step2: Calculate moles of glucose

Given $M = 0.5\ M$ and $V=1\ L$. Rearranging the formula for $n$, we get $n = M\times V$. Substituting the values, $n=0.5\ mol/L\times1\ L = 0.5\ mol$.

Step3: Determine preparation steps

We can weigh out 0.5 moles of glucose (molar - mass of glucose $C_6H_{12}O_6$ is approximately $180\ g/mol$, so mass of glucose $m = n\times molar - mass=0.5\ mol\times180\ g/mol = 90\ g$). Then dissolve this 90 - g of glucose in enough water to make a total volume of 1 liter. So, yes, we can prepare 1 liter of a 0.5 - molar glucose solution.

Molarity is a measure of the concentration of a solute in a solution. It is defined as the number of moles of solute per liter of solution.

Answer:

Yes, by weighing 90 g of glucose and dissolving it in enough water to make 1 liter of solution.

e.