Question

can you show that this quadrilateral is a parallelogram? 62° 118° 62° yes no

Explanation:

Step1: Find the 4th interior angle

Sum of quadrilateral angles is $360^\circ$. Let the unknown angle be $x$.
$x = 360^\circ - (62^\circ + 118^\circ + 62^\circ) = 118^\circ$

Step2: Pair consecutive supplementary angles

Check angle pairs:
$62^\circ + 118^\circ = 180^\circ$, $118^\circ + 62^\circ = 180^\circ$, $62^\circ + 118^\circ = 180^\circ$

Step3: Verify parallel opposite sides

Supplementary consecutive angles mean opposite sides are parallel. So, the quadrilateral has two pairs of parallel sides.

Answer:

yes