Question

you work for the national weather service and are asked to study the average daily temperatures in anchorage, alaska. you calculate the mean of the average daily temperatures for each month. you decide to place the information on a graph in which the date is the input and the temperature is the output. you also decide that january 1950 will correspond to the month 0 as indicated by the dot on the input scale. determine the quadrant in which you would plot the points that correspond to the following data: the average daily temperature for july 1910 was 71°f. a. quadrant iii

Explanation:

Step1: Calculate month number

July 1910 - January 1950: Since 1910 is earlier than 1950, we calculate the number of months. From January 1910 - January 1950, there are \(40\times12 = 480\) months. July 1910 is 6 months after January 1910, so the month number is \(- 480 + 6=-474\) (negative as it is before January 1950).

Step2: Analyze temperature

The temperature is \(71^{\circ}F\) which is positive.

Step3: Determine quadrant

In a coordinate - plane, with month on the x - axis and temperature on the y - axis, a negative x - value (month) and a positive y - value (temperature) places the point in Quadrant II. But there is a mistake in the above step1. Let's correct it. January 1950 is month 0. From January 1910 to January 1950, there are \(40\) years or \(40\times12 = 480\) months. July 1910 is 6 months after January 1910. So the month number (x - value) relative to January 1950 is \(480 - 6=474\) (positive). The temperature (y - value) is \(71^{\circ}F\) (positive). A positive x - value and a positive y - value place the point in Quadrant I.

Answer:

I