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Question
(2, -1) (-2, 3)
Assuming the problem is to find the distance between the two points \((2, -1)\) and \((-2, 3)\), we can use the distance formula.
Step1: Recall the distance formula
The distance \(d\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by \(d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\).
Here, \(x_1 = 2\), \(y_1 = -1\), \(x_2 = -2\), and \(y_2 = 3\).
Step2: Substitute the values into the formula
First, calculate \(x_2 - x_1\) and \(y_2 - y_1\):
\(x_2 - x_1 = -2 - 2 = -4\)
\(y_2 - y_1 = 3 - (-1) = 3 + 1 = 4\)
Step3: Square the differences and sum them
\((x_2 - x_1)^2 = (-4)^2 = 16\)
\((y_2 - y_1)^2 = 4^2 = 16\)
Sum: \(16 + 16 = 32\)
Step4: Take the square root
\(d = \sqrt{32} = \sqrt{16 \times 2} = 4\sqrt{2}\) (or approximately \(5.66\) if a decimal approximation is needed)
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The distance between the points \((2, -1)\) and \((-2, 3)\) is \(4\sqrt{2}\) (or approximately \(5.66\)).